teo123 wrote:
I don't know now. No, and I guess it is because your eyes follow it, so the image plane doesn't stay the same, for the same reason as the horizon seems to raise with you as you go up.
No, it's because if it's at the same distance from you, it doesn't get larger based on perspective just because it's higher up. That's ridiculous.
What you are describing is a pincushion distortion.
teo123 wrote:The difference was barely perceptible, and it could be only because I expected it.
At least you recognize that. If you move off center from a lens, there are also optical distortions (different levels of zoom).
If you wanted to do this properly, you'd have to use a camera and account for that.
The whole idea is based on a misunderstanding of perspective, though.
teo123 wrote:
OK, let me try. Let's not deal with the third dimension, to make things simpler. Let's assume that the ant, looking towards the horizon, is at A(0,0), that the bottom part of the bird on the ground is at B(10,0), that the top part of the bird on the ground is at C(10,10), that the bottom part of the bird in the sky is at D(10,100) and that the top part of the bird in the sky is at E(10,110), and that the image plane is the line x=1 (because, again, we are not dealing with the third dimension).
The ant's lens (assuming it has a human-like eye, which it doesn't) is at that position. It doesn't matter what way the ant is looking unless you assume some kind of distortion from the lens. That's not something you want to deal with to just understand basic perspective.
The image plane is not at x=1. It is a curved surface
behind the eye where the image falls after passing through the lens (assume a pinhole camera).
As such, all of this is complete nonsense:
teo123 wrote:The light ray between A and B is y=0, so the projection of B on the image plane is (where the light ray and the image plane intersect) B'=(1,0). The light ray between C and A is y=x, so C'=(1,1). The light ray between D and A is y=10*x, so D'=(1,10). The light ray between E and A is y=11*x, so E'=(1,11).
Do it again. Draw a correct diagram, and calculate the projections on the back of the eye. Also, if you don't want to move the eye, then keep both birds within the range of human view by moving them both father away along X, or lowering the higher bird and making the birds smaller.
teo123 wrote:Are their projections equal? Yes, they are. It just affirmed my beliefs.
It should not have. If you were wise, and less arrogant, it should have affirmed that you do not understand something very fundamental to perspective and projection.